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解决小黑狗类技能没有阶梯时的问题

tags/v15.0
枫谷剑仙 5 years ago
parent
commit
bbdad28f42
1 changed files with 3 additions and 2 deletions
  1. +3
    -2
      languages/zh-CN.js

+ 3
- 2
languages/zh-CN.js View File

@@ -684,11 +684,12 @@ function parseSkillDescription(skill) {
{
if (hasDiffOrbs)
{//「光光火/光火火」組合的3COMBO時,所有寵物的攻擊力3.5倍;「光光火火」組合的4COMBO或以上時,所有寵物的攻擊力6倍
str = `${strArr.map(a=>nb(a, attrsName)).join("、")}中${sk[5]}串同时攻击时,所有宠物的攻击力×${sk[6]/100}倍,每多1串+${sk[7]/100}倍,最大${strArr.length}串时×${(sk[6]+sk[7]*(strArr.length-sk[5]))/100}倍`;
str = `${strArr.map(a=>nb(a, attrsName)).join("、")}中${sk[5]}串同时攻击时,所有宠物的攻击力×${sk[6]/100}倍`;
}else
{//木寶珠有2COMBO時,所有寵物的攻擊力3倍,每多1COMBO+4倍,最大5COMBO時15倍
str = `${nb(strArr[0], attrsName).join("、")}宝珠有${sk[5]}串时,所有宠物的攻击力×${sk[6]/100}倍,每多1串+${sk[7]/100}倍,最大${strArr.length}串时×${(sk[6]+sk[7]*(strArr.length-sk[5]))/100}倍`;
str = `${nb(strArr[0], attrsName).join("、")}宝珠有${sk[5]}串时,所有宠物的攻击力×${sk[6]/100}倍`;
}
if (sk[7]) str += `,每多1串+${sk[7]/100}倍,最大${strArr.length}串时×${(sk[6]+sk[7]*(strArr.length-sk[5]))/100}倍`;
}else
{
if (hasDiffOrbs)


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