diff --git a/exercise/1_basic/1_python.ipynb b/exercise/1_basic/1_python.ipynb
deleted file mode 100644
index baa1375..0000000
--- a/exercise/1_basic/1_python.ipynb
+++ /dev/null
@@ -1,89 +0,0 @@
-{
- "cells": [
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "# Python & Machine Learning Exercises"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "## Python\n",
- "\n",
- "### （1）字符串\n",
- "给定一个文章，找出每个单词的出现次数\n",
- "\n",
- "```\n",
- "One is always on a strange road, watching strange scenery and listening to strange music. Then one day, you will find that the things you try hard to forget are already gone. \n",
- "```\n",
- "\n",
- "### （2）组合\n",
- "有 1、2、3、4 个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？\n",
- "\n",
- "\n",
- "### （3） 判断\n",
- "企业发放的奖金根据利润提成。利润(I)： \n",
- "* 低于或等于 10 万元时，奖金可提 10%； \n",
- "* 高于 10 万元，低于 20 万元时，低于 10 万元的部分按 10%提成，高于 10 万元的部分，可提成 7.5%； \n",
- "* 20 万到 40 万之间时，高于 20 万元的部分，可提成 5%； \n",
- "* 40 万到 60 万之间时，高于 40 万元的部分，可提成 3%； \n",
- "* 60 万到 100 万之间时，高于 60 万元的部分，可提成 1.5%， \n",
- "* 高于 100 万元时， 超过 100 万元的部分按 1%提成， \n",
- "从键盘输入当月利润 I，求应发放奖金总数？\n",
- "\n",
- "\n",
- "### （4）循环\n",
- "输出9x9的乘法口诀表\n",
- "\n",
- "\n",
- "### （5）使用while循环实现输出2-3+4-5+6.....+100的和\n",
- "\n",
- "\n",
- "### （6）算法\n",
- "给一个数字列表，将其按照由大到小的顺序排列\n",
- "\n",
- "例如\n",
- "```\n",
- "1, 10, 4, 2, 9, 2, 34, 5, 9, 8, 5, 0\n",
- "```\n",
- "\n",
- "### （7）应用1\n",
- "做为 Apple Store App 独立开发者，你要搞限时促销，为你的应用生成激活码（或者优惠券），使用 Python 如何生成 200 个激活码（或者优惠券）？\n",
- "\n",
- "需要考虑什么是激活码？有什么特性？例如`KR603guyVvR`是一个激活码\n",
- "\n",
- "### （8）应用2\n",
- "需要把某个目录下面所有的某种类型的文件找到。\n",
- "例如把`c:`下面所有的`.dll`文件找到\n",
- "\n",
- "### （9）应用3\n",
- "你有个目录，里面是程序（假如是C或者是Python），统计一下你写过多少行代码。包括空行和注释，但是要分别列出来。\n",
- "\n"
- ]
- }
- ],
- "metadata": {
- "kernelspec": {
- "display_name": "Python 3",
- "language": "python",
- "name": "python3"
- },
- "language_info": {
- "codemirror_mode": {
- "name": "ipython",
- "version": 3
- },
- "file_extension": ".py",
- "mimetype": "text/x-python",
- "name": "python",
- "nbconvert_exporter": "python",
- "pygments_lexer": "ipython3",
- "version": "3.5.2"
- }
- },
- "nbformat": 4,
- "nbformat_minor": 2
-}
diff --git a/exercise/1_basic/1_python.py b/exercise/1_basic/1_python.py
deleted file mode 100644
index 393c30b..0000000
--- a/exercise/1_basic/1_python.py
+++ /dev/null
@@ -1,74 +0,0 @@
-# -*- coding: utf-8 -*-
-# ---
-# jupyter:
-# jupytext_format_version: '1.2'
-# kernelspec:
-# display_name: Python 3
-# language: python
-# name: python3
-# language_info:
-# codemirror_mode:
-# name: ipython
-# version: 3
-# file_extension: .py
-# mimetype: text/x-python
-# name: python
-# nbconvert_exporter: python
-# pygments_lexer: ipython3
-# version: 3.5.2
-# ---
-
-# # Python & Machine Learning Exercises
-
-# ## Python
-#
-# ### （1）字符串
-# 给定一个文章，找出每个单词的出现次数
-#
-# ```
-# One is always on a strange road, watching strange scenery and listening to strange music. Then one day, you will find that the things you try hard to forget are already gone.
-# ```
-#
-# ### （2）组合
-# 有 1、2、3、4 个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？
-#
-#
-# ### （3） 判断
-# 企业发放的奖金根据利润提成。利润(I)：
-# * 低于或等于 10 万元时，奖金可提 10%；
-# * 高于 10 万元，低于 20 万元时，低于 10 万元的部分按 10%提成，高于 10 万元的部分，可提成 7.5%；
-# * 20 万到 40 万之间时，高于 20 万元的部分，可提成 5%；
-# * 40 万到 60 万之间时，高于 40 万元的部分，可提成 3%；
-# * 60 万到 100 万之间时，高于 60 万元的部分，可提成 1.5%，
-# * 高于 100 万元时， 超过 100 万元的部分按 1%提成，
-# 从键盘输入当月利润 I，求应发放奖金总数？
-#
-#
-# ### （4）循环
-# 输出9x9的乘法口诀表
-#
-#
-# ### （5）使用while循环实现输出2-3+4-5+6.....+100的和
-#
-#
-# ### （6）算法
-# 给一个数字列表，将其按照由大到小的顺序排列
-#
-# 例如
-# ```
-# 1, 10, 4, 2, 9, 2, 34, 5, 9, 8, 5, 0
-# ```
-#
-# ### （7）应用1
-# 做为 Apple Store App 独立开发者，你要搞限时促销，为你的应用生成激活码（或者优惠券），使用 Python 如何生成 200 个激活码（或者优惠券）？
-#
-# 需要考虑什么是激活码？有什么特性？例如`KR603guyVvR`是一个激活码
-#
-# ### （8）应用2
-# 需要把某个目录下面所有的某种类型的文件找到。
-# 例如把`c:`下面所有的`.dll`文件找到
-#
-# ### （9）应用3
-# 你有个目录，里面是程序（假如是C或者是Python），统计一下你写过多少行代码。包括空行和注释，但是要分别列出来。
-#
-#
diff --git a/exercise/1_basic/2_numpy.ipynb b/exercise/1_basic/2_numpy.ipynb
deleted file mode 100644
index 2a7a643..0000000
--- a/exercise/1_basic/2_numpy.ipynb
+++ /dev/null
@@ -1,82 +0,0 @@
-{
- "cells": [
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "## 数值计算\n",
- "\n",
- "\n",
- "### （1）对于一个存在在数组，如何添加一个用0填充的边界?\n",
- "例如对一个二维矩阵\n",
- "```\n",
- "10, 34, 54, 23\n",
- "31, 87, 53, 68\n",
- "98, 49, 25, 11\n",
- "84, 32, 67, 88\n",
- "```\n",
- "\n",
- "变换成\n",
- "```\n",
- " 0, 0, 0, 0, 0, 0\n",
- " 0, 10, 34, 54, 23, 0\n",
- " 0, 31, 87, 53, 68, 0\n",
- " 0, 98, 49, 25, 11, 0\n",
- " 0, 84, 32, 67, 88, 0\n",
- " 0, 0, 0, 0, 0, 0\n",
- "```\n",
- "\n",
- "### （2） 创建一个 5x5的矩阵，并设置值1,2,3,4落在其对角线下方位置\n",
- "\n",
- "\n",
- "### （3） 创建一个8x8 的矩阵，并且设置成国际象棋棋盘样式（黑可以用0, 白可以用1）\n",
- "\n",
- "\n",
- "### （4）求解线性方程组\n",
- "\n",
- "给定一个方程组，如何求出其的方程解。有多种方法，分析各种方法的优缺点（最简单的方式是消元方）。\n",
- "\n",
- "例如\n",
- "```\n",
- "3x + 4y + 2z = 10\n",
- "5x + 3y + 4z = 14\n",
- "8x + 2y + 7z = 20\n",
- "```\n",
- "\n",
- "编程写出求解的程序\n",
- "\n",
- "\n",
- "### （5） 翻转一个数组（第一个元素变成最后一个）\n",
- "\n",
- "\n",
- "### （6） 产生一个十乘十随机数组，并且找出最大和最小值\n",
- "\n",
- "\n",
- "## Reference\n",
- "* [100 numpy exercises](https://github.com/rougier/numpy-100)"
- ]
- }
- ],
- "metadata": {
- "kernelspec": {
- "display_name": "Python 3",
- "language": "python",
- "name": "python3"
- },
- "language_info": {
- "codemirror_mode": {
- "name": "ipython",
- "version": 3
- },
- "file_extension": ".py",
- "mimetype": "text/x-python",
- "name": "python",
- "nbconvert_exporter": "python",
- "pygments_lexer": "ipython3",
- "version": "3.5.2"
- },
- "main_language": "python"
- },
- "nbformat": 4,
- "nbformat_minor": 2
-}
diff --git a/exercise/1_basic/2_numpy.py b/exercise/1_basic/2_numpy.py
deleted file mode 100644
index 0b53cd7..0000000
--- a/exercise/1_basic/2_numpy.py
+++ /dev/null
@@ -1,70 +0,0 @@
-# -*- coding: utf-8 -*-
-# ---
-# jupyter:
-# jupytext_format_version: '1.2'
-# kernelspec:
-# display_name: Python 3
-# language: python
-# name: python3
-# language_info:
-# codemirror_mode:
-# name: ipython
-# version: 3
-# file_extension: .py
-# mimetype: text/x-python
-# name: python
-# nbconvert_exporter: python
-# pygments_lexer: ipython3
-# version: 3.5.2
-# ---
-
-# ## 数值计算
-#
-#
-# ### （1）对于一个存在在数组，如何添加一个用0填充的边界?
-# 例如对一个二维矩阵
-# ```
-# 10, 34, 54, 23
-# 31, 87, 53, 68
-# 98, 49, 25, 11
-# 84, 32, 67, 88
-# ```
-#
-# 变换成
-# ```
-# 0, 0, 0, 0, 0, 0
-# 0, 10, 34, 54, 23, 0
-# 0, 31, 87, 53, 68, 0
-# 0, 98, 49, 25, 11, 0
-# 0, 84, 32, 67, 88, 0
-# 0, 0, 0, 0, 0, 0
-# ```
-#
-# ### （2） 创建一个 5x5的矩阵，并设置值1,2,3,4落在其对角线下方位置
-#
-#
-# ### （3） 创建一个8x8 的矩阵，并且设置成国际象棋棋盘样式（黑可以用0, 白可以用1）
-#
-#
-# ### （4）求解线性方程组
-#
-# 给定一个方程组，如何求出其的方程解。有多种方法，分析各种方法的优缺点（最简单的方式是消元方）。
-#
-# 例如
-# ```
-# 3x + 4y + 2z = 10
-# 5x + 3y + 4z = 14
-# 8x + 2y + 7z = 20
-# ```
-#
-# 编程写出求解的程序
-#
-#
-# ### （5） 翻转一个数组（第一个元素变成最后一个）
-#
-#
-# ### （6） 产生一个十乘十随机数组，并且找出最大和最小值
-#
-#
-# ## Reference
-# * [100 numpy exercises](https://github.com/rougier/numpy-100)
diff --git a/exercise/1_basic/3_matplotlib.ipynb b/exercise/1_basic/3_matplotlib.ipynb
deleted file mode 100644
index 71b36e5..0000000
--- a/exercise/1_basic/3_matplotlib.ipynb
+++ /dev/null
@@ -1,37 +0,0 @@
-{
- "cells": [
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "# Matplotlib\n",
- "\n",
- "\n",
- "## (1) 画出一个二次函数，同时画出梯形法求积分时的各个梯形\n",
- "\n"
- ]
- }
- ],
- "metadata": {
- "kernelspec": {
- "display_name": "Python 3",
- "language": "python",
- "name": "python3"
- },
- "language_info": {
- "codemirror_mode": {
- "name": "ipython",
- "version": 3
- },
- "file_extension": ".py",
- "mimetype": "text/x-python",
- "name": "python",
- "nbconvert_exporter": "python",
- "pygments_lexer": "ipython3",
- "version": "3.5.2"
- },
- "main_language": "python"
- },
- "nbformat": 4,
- "nbformat_minor": 2
-}
diff --git a/exercise/1_basic/3_matplotlib.py b/exercise/1_basic/3_matplotlib.py
deleted file mode 100644
index 9c0d808..0000000
--- a/exercise/1_basic/3_matplotlib.py
+++ /dev/null
@@ -1,26 +0,0 @@
-# -*- coding: utf-8 -*-
-# ---
-# jupyter:
-# jupytext_format_version: '1.2'
-# kernelspec:
-# display_name: Python 3
-# language: python
-# name: python3
-# language_info:
-# codemirror_mode:
-# name: ipython
-# version: 3
-# file_extension: .py
-# mimetype: text/x-python
-# name: python
-# nbconvert_exporter: python
-# pygments_lexer: ipython3
-# version: 3.5.2
-# ---
-
-# # Matplotlib
-#
-#
-# ## (1) 画出一个二次函数，同时画出梯形法求积分时的各个梯形
-#
-#
diff --git a/exercise/2_交通事故理赔审核预测/Exercise - 交通事故理赔审核预测.ipynb b/exercise/2_交通事故理赔审核预测/Exercise - 交通事故理赔审核预测.ipynb
deleted file mode 100644
index ca68092..0000000
--- a/exercise/2_交通事故理赔审核预测/Exercise - 交通事故理赔审核预测.ipynb
+++ /dev/null
@@ -1,931 +0,0 @@
-{
- "cells": [
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "# Exercise - 交通事故理赔审核预测\n",
- "\n",
- "\n",
- "这个比赛的链接：http://sofasofa.io/competition.php?id=2\n",
- "\n",
- "\n",
- "* 任务类型：二元分类\n",
- "\n",
- "* 背景介绍：在交通摩擦（事故）发生后，理赔员会前往现场勘察、采集信息，这些信息往往影响着车主是否能够得到保险公司的理赔。训练集数据包括理赔人员在现场对该事故方采集的36条信息，信息已经被编码，以及该事故方最终是否获得理赔。我们的任务是根据这36条信息预测该事故方没有被理赔的概率。\n",
- "\n",
- "* 数据介绍：训练集中共有200000条样本，预测集中有80000条样本。 \n",
- "\n",
- "\n",
- "* 评价方法：Precision-Recall AUC\n"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "## Demo code\n"
- ]
- },
- {
- "cell_type": "code",
- "execution_count": 2,
- "metadata": {},
- "outputs": [],
- "source": [
- "import pandas as pd\n",
- "import numpy as np\n",
- "import os\n",
- "import matplotlib.pyplot as plt\n",
- "%matplotlib inline"
- ]
- },
- {
- "cell_type": "code",
- "execution_count": 45,
- "metadata": {},
- "outputs": [],
- "source": [
- "# read data\n",
- "homePath = \"data\"\n",
- "trainPath = os.path.join(homePath, \"train.csv\")\n",
- "testPath = os.path.join(homePath, \"test.csv\")\n",
- "submitPath = os.path.join(homePath, \"sample_submit.csv\")\n",
- "trainData = pd.read_csv(trainPath)\n",
- "testData = pd.read_csv(testPath)\n",
- "submitData = pd.read_csv(submitPath)"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "参照数据说明，CaseID这列是没有意义的编号，因此这里将他丢弃。\n",
- "\n",
- "~drop()函数：axis指沿着哪个轴，0为行，1为列；inplace指是否在原数据上直接操作\n"
- ]
- },
- {
- "cell_type": "code",
- "execution_count": 46,
- "metadata": {},
- "outputs": [],
- "source": [
- "# 去掉没有意义的一列\n",
- "trainData.drop(\"CaseId\", axis=1, inplace=True)\n",
- "testData.drop(\"CaseId\", axis=1, inplace=True)"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "# 快速了解数据\n",
- "\n",
- "~head()：默认显示前5行数据，可指定显示多行，例如.head(15)显示前15行\n"
- ]
- },
- {
- "cell_type": "code",
- "execution_count": 30,
- "metadata": {},
- "outputs": [
- {
- "data": {
- "text/html": [
- "\n",
- "\n",
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15 rows × 37 columns
\n",
- "