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解决协力排序时,没有计算297的问题。之前明明解决的问题,不知道代码为什么不见了。

tags/v6.5
枫谷剑仙 6 years ago
parent
commit
6726e8d68c
1 changed files with 6 additions and 6 deletions
  1. +6
    -6
      script-json_data.js

+ 6
- 6
script-json_data.js View File

@@ -78,16 +78,16 @@ if (!solo)
{
const multiSort = [
{tag:"sort_hpMax110_Multi",name:"最大协力攻击(Lv110)",function:(a,b)=>
a.atk.max * (1 + a.limitBreakIncr/100) * Math.pow(1.5, a.awakenings.filter(ak=>ak===30).length) -
b.atk.max * (1 + b.limitBreakIncr/100) * Math.pow(1.5, b.awakenings.filter(ak=>ak===30).length)
(a.atk.max * (1 + a.limitBreakIncr/100) + 495) * Math.pow(1.5, a.awakenings.filter(ak=>ak===30).length) -
(b.atk.max * (1 + b.limitBreakIncr/100) + 495) * Math.pow(1.5, b.awakenings.filter(ak=>ak===30).length)
},
{tag:"sort_hpMax110_Multi",name:"最大协力HP(Lv110)",function:(a,b)=>
a.hp.max * (1 + a.limitBreakIncr/100) * Math.pow(1.5, a.awakenings.filter(ak=>ak===30).length) -
b.hp.max * (1 + b.limitBreakIncr/100) * Math.pow(1.5, b.awakenings.filter(ak=>ak===30).length)
(a.hp.max * (1 + a.limitBreakIncr/100) + 990) * Math.pow(1.5, a.awakenings.filter(ak=>ak===30).length) -
(b.hp.max * (1 + b.limitBreakIncr/100) + 990) * Math.pow(1.5, b.awakenings.filter(ak=>ak===30).length)
},
{tag:"sort_hpMax110_Multi",name:"最大协力回复(Lv110)",function:(a,b)=>
a.rcv.max * (1 + a.limitBreakIncr/100) * Math.pow(1.5, a.awakenings.filter(ak=>ak===30).length) -
b.rcv.max * (1 + b.limitBreakIncr/100) * Math.pow(1.5, b.awakenings.filter(ak=>ak===30).length)
(a.rcv.max * (1 + a.limitBreakIncr/100) + 99) * Math.pow(1.5, a.awakenings.filter(ak=>ak===30).length) -
(b.rcv.max * (1 + b.limitBreakIncr/100) + 99) * Math.pow(1.5, b.awakenings.filter(ak=>ak===30).length)
},
];
sort_function_list.push(...multiSort);

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